| Pages: [1] :: one page |
|
|
| Author |
Topic |
Chicky Poo
    |
Posted - 2008.09.04 23:07:00 -
[1]
Quick question:
If you use a max run BPC on a Mod, you get ___?___ run T2.
If you don't use max run BPC on a Mod, you get __?__ run T2.
If you use a max run BPC on a Ship, you get ___?___ run T2.
If you don't use max run BPC on a Ship, you get __?__ run T2.
What would be the answers if no extras were used?
Thanks
|
Chicky Poo
|
Posted - 2008.09.04 23:16:00 -
[2]
I ask this cause I am trying to find out the benifit of use a max run ship copy on an invention job. Seems like both non-max runs bpc and max run bpc get the same final T2 BPC run result.
Mod I think you get an additional +9 for a max run copy.
Thanks again
|
RenTek
|
Posted - 2008.09.05 06:34:00 -
[3]
Whenever you use a decryptor you basically get +1 run on a ship bpc. You have to use the decryptor though else you don't get it. |
SeismicForce
The Shadow Order
Vanguard.
|
Posted - 2008.09.05 07:50:00 -
[4]
Max run module BPC gives you a 10 run T2 BPC, anything less than max only a 1 run (I think)
Max run ship BPC gives you a 1 run T2 bpc, the number of runs is modified by the decryptor used.
So, if you don't use decryptors there is no point in using max run ship bpc's.
 Originally by: Allisie
In a recent interview, a dev mentioned that ships and skills cause lag and will be removed in EVE 2.
|
grokouik
Caldari
Scordite Mining Inc
|
Posted - 2008.09.05 08:59:00 -
[5]
If you use a max run BPC on a Mod, you get ___?___ run T2.
10+decryptor modifier (but, well, don't use decryptor on mods, they are too costly for that ^^)
If you don't use max run BPC on a Mod, you get __?__ run T2.
max(1,10*truncate(nb run on BPC/nb max BPC run)+decryptor modifier)
If you use a max run BPC on a Ship, you get ___?___ run T2.
1+decryptor modifier
If you don't use max run BPC on a Ship, you get __?__ run T2.
max(1,0+decryptor modifier)
|
grokouik
Caldari
Scordite Mining Inc
|
Posted - 2008.09.05 08:59:00 -
[6]
Edited by: grokouik on 05/09/2008 09:00:04
Sorry for double post, got a 500/internal server error on first try :)
|
Chicky Poo
|
Posted - 2008.09.05 11:17:00 -
[7]
Edited by: Chicky Poo on 05/09/2008 11:19:40
So say you use the +1run decryptor on a max run ship BPC. You will get a T2 BPC with +2 runs.
Now what happens if you use a non-max run BPC, do you only get a T2 ship BPC with 1run?
Then what happens if you use a non-max ship BPC, with no decryptor? How many runs will you get then?
Finally, what happens on a non-max bpc if you use it with a +0 decryptor?
And then the same type of decryptor with a max ship BPC?
Thanks
|
Lord Fitz
Project Amargosa
|
Posted - 2008.09.05 11:33:00 -
[8]
The formula for output runs is:
round down((Input Runs / T1 Production Limit) * (T2 Production Limit / 10) + decryptor runs)
There is also a minimum of 1 run output if successful, so the above if it rounds down to 0 you still get 1 run.
For modules you get 10 runs base, so if you put in half of max runs, you get 5 runs instead of 10. If you put just 1 run less than max you get only 9 instead of 10. If you put in 1 run input you only get 1 run output. So for modules, given how quick they are to copy, it's worth always using max runs.
For ships, the T2 production Limit is 10, so 1 base run. Which means that without a decryptor that adds runs, you will always get a 1 run output regardless of the input. But, if you are using a +runs decryptor, you won't be losing that run.
say a cruiser invention with 1 run input with a +9 decryptor:
((1/15) * (10/10)) + 9 = 9.07 which rounds down to 9 runs output
but with max runs
((15/15) * (10/10) + 9 = 10 runs.
|
Lord Fitz
Project Amargosa
|
Posted - 2008.09.05 11:36:00 -
[9]
Originally by: Chicky Poo
Edited by: Chicky Poo on 05/09/2008 11:19:40
So say you use the +1run decryptor on a max run ship BPC. You will get a T2 BPC with +2 runs.
Now what happens if you use a non-max run BPC, do you only get a T2 ship BPC with 1run?
Then what happens if you use a non-max ship BPC, with no decryptor? How many runs will you get then?
Finally, what happens on a non-max bpc if you use it with a +0 decryptor?
And then the same type of decryptor with a max ship BPC?
Thanks
The reason using less than max runs with ships works is because the minimum you get is 1 run, and the normal output without decryptors is 1 run, thus for all ship invention without a decryptor you get 1 run, regardless of the input. If you use a +1 with max, you get 2, but with a +1 and any less than max run input you only get 1. For +9 you will get 10 runs with a max run and only 9 for anything less.
|
deathatlaby
NAUCOM
|
Posted - 2008.09.06 02:10:00 -
[10]
Originally by: Lord Fitz
The formula for output runs is:
round down((Input Runs / T1 Production Limit) * (T2 Production Limit / 10) + decryptor runs)
There is also a minimum of 1 run output if successful, so the above if it rounds down to 0 you still get 1 run.
For modules you get 10 runs base, so if you put in half of max runs, you get 5 runs instead of 10. If you put just 1 run less than max you get only 9 instead of 10. If you put in 1 run input you only get 1 run output. So for modules, given how quick they are to copy, it's worth always using max runs.
For ships, the T2 production Limit is 10, so 1 base run. Which means that without a decryptor that adds runs, you will always get a 1 run output regardless of the input. But, if you are using a +runs decryptor, you won't be losing that run.
say a cruiser invention with 1 run input with a +9 decryptor:
((1/15) * (10/10)) + 9 = 9.07 which rounds down to 9 runs output
but with max runs
((15/15) * (10/10) + 9 = 10 runs.
Lord, Is the formula always RoundDown or Round?
★★★NAUCOM T2 SHIP STORE★★★ |
|
Lord Fitz
Project Amargosa
|
Posted - 2008.09.06 04:26:00 -
[11]
Originally by: deathatlaby
Originally by: Lord Fitz
The formula for output runs is:
round down((Input Runs / T1 Production Limit) * (T2 Production Limit / 10) + decryptor runs)
There is also a minimum of 1 run output if successful, so the above if it rounds down to 0 you still get 1 run.
For modules you get 10 runs base, so if you put in half of max runs, you get 5 runs instead of 10. If you put just 1 run less than max you get only 9 instead of 10. If you put in 1 run input you only get 1 run output. So for modules, given how quick they are to copy, it's worth always using max runs.
For ships, the T2 production Limit is 10, so 1 base run. Which means that without a decryptor that adds runs, you will always get a 1 run output regardless of the input. But, if you are using a +runs decryptor, you won't be losing that run.
say a cruiser invention with 1 run input with a +9 decryptor:
((1/15) * (10/10)) + 9 = 9.07 which rounds down to 9 runs output
but with max runs
((15/15) * (10/10) + 9 = 10 runs.
Lord, Is the formula always RoundDown or Round?
It always rounds down, but has a minimum of 1.
So for say excel =MAX(ROUNDDOWN(((INPUT_RUNS/T1_Production_LIMIT)*(T2_Production_Limit/10)),0)+DECRYPTOR_RUNS),1)
|
Mohira
|
Posted - 2008.09.06 13:13:00 -
[12]
Could someone please redirect me to a web link that explains how T2 research works ?
What are decryptors and such ?
Thx
|
Lord Fitz
Project Amargosa
|
Posted - 2008.09.06 14:53:00 -
[13]
http://www.eve-guides.com/ittey/index.php
That link has a guide, some parts of it are fairly out of date, but the actual 'what is invention and what does it do' bits are still all the same, so it's a good read if you need a general introduction.
|
Barbicane
TGUN Industries
|
Posted - 2008.09.07 21:00:00 -
[14]
There is a web-based calculator for invention chance here.
I've found it to be reasonably accurate.
|
|
| Pages: [1] :: one page |
| First page | Previous page | Next page | Last page |