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Krishan13
Bright Nova Industries
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Posted - 2009.11.10 20:21:00 -
[1]
I've been inventing some T2 large CCC rigs, and noticed something strange.
When using an amarr Formation Layout decryptor, I should be getting -1ME -1PE and 1 run per BPC.
Instead, I've been getting 3-run BPCs.
Now, I've been using max-run CCC BPCs to invent from, but for rigs I thought # of runs didn't matter? What's causing the 3-run BPCs?
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Ruziel
Minmatar Twilight Military Industrial Complex
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Posted - 2009.11.10 20:51:00 -
[2]
The number of runs does matter, for the math:
http://www.eveonline.com/ingameboard.asp?a=topic&threadID=1205778 |

Tau Cabalander
Caldari
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Posted - 2009.11.10 21:36:00 -
[3]
From all the reading I've done, rigs don't seem to obey the formula.
If you don't use a decrypter, you can only get a 1 run T2 BPC.
If you use any decrypter with a max run T1 BPC, you get a random number of runs (max 3), plus any bonus runs from the decrypter (max 3 + 1 = 4).
From all I've read 4 runs is known to happen when using a +1 run decrypter, but is very rare.
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Krishan13
Bright Nova Industries
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Posted - 2009.11.10 21:37:00 -
[4]
Yes, but afaik rigs are the same as ships: the number of runs on the BPC has no effect on the # of runs on the result. Only the decryptor bonus runs affects things - and a Formation Layout is a +0 runs decryptor.
Further, a 1000-run T1 rig BPC produces a 1-run T2 BPC without a decryptor. So why would it produce a 3-run BPC with a +0 run decryptor?
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Modescond
Minmatar Twilight Military Industrial Complex
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Posted - 2009.11.10 21:56:00 -
[5]
Edited by: Modescond on 10/11/2009 21:56:49 Let me guess, you have 1000 run T1 prints made before the cutover? If so, then the formula is correct.
MAX((T1Runs / T1MaxRuns) * (T2MaxRuns / 10) + DecryptorMod, 1)
Normally T1Runs / T1MaxRuns is a number between 0 and 1, however, in your case, it comes out to just over 3. As a result, you end up with 3 times the number of runs.
Based on that, you'll get 3-run ME-1 T2 prints :)
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Lord Fitz
Project Amargosa
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Posted - 2009.11.11 02:05:00 -
[6]
ALL INVENTION follows this formula for runs
Output Runs = min(max( round down ( (InputBPCRuns / T1MaxRunsPerBlueprintCopy) * (T2MaxRunsPerBlueprintCopy / 10) + DecryptorRuns ), 1), T2MaxRunsPerBlueprintCopy)
The formula still applies, even if CCP make changes to blueprint attributes (which is what led to the discovery of the finer points). This is 'the' formula. It ALWAYS applies.
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