class p
{
public:
p(const char *a) : _p(a) {}
char *operator+(const char *b)
{return strcat(strcpy(new char[strlen(_p)+strlen(b)+1], _p), b);}

private:
const char *_p;
};

...

c = p(a) + b;

Originally by: Kaeten

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char a[10]="hey_",b[10]="du_",c[}="";
c=a+b;

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Originally by: Barbarellas Daughter

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Originally by: Kaeten

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char a[10]="hey_",b[10]="du_",c[}="";
c=a+b;

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"hey_du_" ??

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Originally by: Darth Vroevl

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Joining the strings together is as easy as
c=strcat(strcpy(new char[strlen(a)+strlen(b)+1], a), b); , but I'm pretty sure you cant override the built in operators - at least my compiler insists that one of the parameters of + be a userdefined class.

You can probably work around it with something like

class p
{
public:
p(const char *a) : _p(a) {}
char *operator+(const char *b)
{return strcat(strcpy(new char[strlen(_p)+strlen(b)+1], _p), b);}

private:
const char *_p;
};

...

c = p(a) + b;

Though its a bit akward.

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Originally by: Kaeten

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I was also to use the help if OS (outstream) operator=()

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 friend ostream& operator<<(ostream& aOs, const YourClass& aObj);

Originally by: Vmir Gallahasen

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Edited by: Vmir Gallahasen on 29/04/2007 20:53:08

Originally by: Kaeten

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I was also to use the help if OS (outstream) operator=()

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If you're asking how to do that ...?
Not completely sure what you mean, using operator= with outstream? Here's how you do
ostream with <<, perhaps it will give you some ideas.

 friend ostream& operator<<(ostream& aOs, const YourClass& aObj);

Make sure you return a reference to ostream when you're done with it.

-Vmir

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#define + <<

char a[10]="hey_",b[10]="du_";
cout << a + b;

Originally by: Turiya Flesharrower

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string a = "hey_";
atring b = "du_";
string c = a + b;
cout << c << endl;

Or, if you really need to use char arrays:

char a[10] = "hey_";
char b[10] = "du_";
char c[20];
strcpy(c, a);
strcat(c, b);

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