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Publicus Paulus
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Posted - 2008.02.20 21:53:00 -
[1]
Hey,
I'm doing some tinkering with EFT for a fitting in which locking time is very important. So, i'm wondering how i can calculate this, considering i know both the scan resolution of my ship as the signature radius of the opponents ship. Can anyone help with this?
Tx,
Publicus
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Stafen
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Posted - 2008.02.20 22:41:00 -
[2]
It is in the EWar guide:
http://oldforums.eveonline.com/?a=topic&threadID=511720#5
It says:
T = (40000/(M*X))/(asinh(Y)^2)
Where X = scan resolution of your ship with positive bonuses applied, Y = sig radius of the target, M the scan resolution reduction multiplier of the dampening module or drone and T the locking time.
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Publicus Paulus
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Posted - 2008.02.20 23:04:00 -
[3]
Thanks for the fast answer. I have to look over my mathematics again i think.
If anyone can explain wat the asinh(Y)^2 part means i would be even more thankful 
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Gamesguy
Amarr
D00M.
Triumvirate.
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Posted - 2008.02.20 23:42:00 -
[4]
 Originally by: Publicus Paulus
Thanks for the fast answer. I have to look over my mathematics again i think.
If anyone can explain wat the asinh(Y)^2 part means i would be even more thankful
asinh is the inverse function of sinh, and it should be on your calculator.
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Tavoin Tau
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Posted - 2008.02.20 23:48:00 -
[5]
Originally by: Gamesguy
Originally by: Publicus Paulus
Thanks for the fast answer. I have to look over my mathematics again i think.
If anyone can explain wat the asinh(Y)^2 part means i would be even more thankful
asinh is the inverse function of sinh, and it should be on your calculator.
asinh (Hyperbolic arc sine) is not normally on a caculator.
asinh(x) = log(x+sqrt(1+x^2))
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Last Wolf
Templars of Space
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Posted - 2008.02.20 23:50:00 -
[6]
the asinh(x) function squared.
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Last Wolf
Templars of Space
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Posted - 2008.02.20 23:51:00 -
[7]
Originally by: Tavoin Tau
asinh(x) = log(x+sqrt(1+x^2))
Is that sinh(x) or asinh(x)? because it doesn't seem like an inverse to me
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Tavoin Tau
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Posted - 2008.02.21 00:02:00 -
[8]
well not quiet sure how to derive it, but wikipedia says that it is the inverse. http://en.wikipedia.org/wiki/Inverse_hyperbolic_function
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Last Wolf
Templars of Space
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Posted - 2008.02.21 00:15:00 -
[9]
Edited by: Last Wolf on 21/02/2008 00:20:11
Unless my algebra is REALLY bad (probably is)... Using logarithmic properties I simplified that down to
log(x + sqrt(1+x^2))
= log(x) + (1/2)log(1 + x^2)
= log(x) + (1/2)log(1) + log(x)
= 2log(x) + (1/2)(0)
= 2log(x)
Edit. my algebra is bad. Just checked it on the calculator.
Maybe I can only do that stuff with ln(x)? or maybe I'm just crazy.\
hmm I coulda sworn log(x+y) was equal to log(x) + log(y)
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Lena Kanto
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Posted - 2008.02.21 00:25:00 -
[10]
Edited by: Lena Kanto on 21/02/2008 00:25:19
Afaik it's on the windows calculator even.
Start > Run > Calc > Press Enter > Set Scientific Mode if it isn't already.
Type in all the stuff, then when you have asinh(Y)^2 you fill in Y, then tick Inverse and tick Hyp and then press sin, then the x^2.
Pretty sure that yields correct stuffz.
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Sharker2k3
Minmatar
Brutor tribe
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Posted - 2008.02.21 00:36:00 -
[11]
wow, way overcomplicating people. if a calculator has sin on it, there is a 95% chance it has arcsin, its normally just the second function of the sin button. sin squared is (sin(Y)) ^ 2 so arcsin squared is (asin(Y)) ^ 2
(40000/(M*X))
T = ---------------
(asinh(Y))^2
However, I have spotted a wee bit of a problem with this. The fact that Y would have to be between 0 and 1 otherwise the arcsin yields a domain error.
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http://i7.photobucket.com/albums/y285/Sharker2k3/Quit.jpg |
Last Wolf
Templars of Space
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Posted - 2008.02.21 00:39:00 -
[12]
asinh(x)
not asin(x)
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Sharker2k3
Minmatar
Brutor tribe
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Posted - 2008.02.21 00:41:00 -
[13]
ah yes that would change things.
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http://i7.photobucket.com/albums/y285/Sharker2k3/Quit.jpg |
Moo Unit
Zzz
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Posted - 2008.02.21 02:11:00 -
[14]
For the math challenged amongst us, there is also this calculator here.
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Sokratesz
Rionnag Alba
Triumvirate.
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Posted - 2008.02.21 07:15:00 -
[15]
Originally by: Moo Unit
For the math challenged amongst us,
:( you hurt my eeeeeego
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