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Khrys
Minmatar
Republic Military School
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Posted - 2008.09.09 07:20:00 -
[1]
After reviewing all the forums and reading a lot of material , I`m still not sure on the following:
Is using a more-than-one-run BPC improves anything ? (Chance )
If I have a 10 Run BPC and I`m running invention , will it improve my chances of success ? (more than running invention on a 1 run T1 BPC)
If I have a 10 run BPC that I`m running an invention on , is there a chance of getting a 10 run T2 BPC as result ?
I`m realy confused ...
Thx
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Satrani Destiva
Caldari
Just Another Indy Corp
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Posted - 2008.09.09 08:09:00 -
[2]
Edited by: Satrani Destiva on 09/09/2008 08:14:02
The only reason to use more than a 1 run BPC is when you are using a multiple run decryptor, as a maximum run BPC will give an extra run on top of the end product (at least when inventing ships).
eg.
1 run merlin print no decryptor = 1 run hawk/harpy print (if successful)
1 run merlin print with +9 decryptor = 9 run hawk/harpy print (if successful)
10 run merlin print no decryptor = 1 run hawk/harpy print (if successful)
10 run merlin print with +9 decryptor = 10 run hawk/harpy print (if successful)
Using higher me/pe/runs doesn't improve chance or runs without using a decryptor. This site should give you a head start
I haven't done any component invention yet and I know that certain things are different so I can't comment on that.
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Galtan Deus
The Dead Parrot Shoppe Inc.
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Posted - 2008.09.09 11:33:00 -
[3]
The above applies for ship invention. For the vast majority of modules you use a max-run t1 bpc to get a 10-run t2 bpc. The runs make no difference to the chance of success - they just affect the runs on the t2 bpc.
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Matthew
Caldari
BloodStar Technologies
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Posted - 2008.09.09 11:37:00 -
[4]
Edited by: Matthew on 09/09/2008 11:39:05
 Originally by: Satrani Destiva
I haven't done any component invention yet and I know that certain things are different so I can't comment on that.
Doing components actually lets you see the full rule in effect.
Each T2 blueprint has a maximum number of runs that you can invent into a single T2 BPC. You only realise this maximum number if you use a maximum run T1 BPC in the job.
If the T1 BPC has less than max runs, then the resulting T2 BPC will have proportionately less runs as well (e.g. if your T1 BPC has only half it's maximum number of runs, then the resulting T2 BPC will also have only half it's maximum number of runs).
Where this would result in fractions of a run, they are rounded, but with the condition that it can never be less than 1 run.
Ships become a special case, because T2 ship BPC's have a max of 1 inventable run. Hence:
1 run merlin print no decryptor: 1*(1/10)=0.1 -> forced to 1 run
1 run merlin print with +9 decryptor: 1*(1/10)+9 = 9.1 -> rounded to 9 runs
10 run merlin print no decryptor: 1*(10/10)=1 -> 1 run
10 run merlin print with +9 decryptor = 1*(10/10)+9=10 -> 10 runs
So yes, in this case you should only bother with a max-run ship BPC if you are using a decryptor that adds to the number of runs.
However, if the max T2 runs is higher than 1 (as it is with modules), then using a max-run BPC does make a significant difference.
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There is no magic Wand of Fixing, and it is not powered by forum whines. |
Khrys
Minmatar
Republic Military School
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Posted - 2008.09.10 08:28:00 -
[5]
Thx very much for the help
That cleared up my head a little bit ...
Khrys
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Oli Robbo
Gallente
Galactic Defence Syndicate
Axiom Empire
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Posted - 2008.09.10 11:25:00 -
[6]
ok so say you're doing ship invention going by the above formula's.. it appears that it would be more efficient/economical to use a 1run bpc and a decryptor to get a 9run copy rather than using a 10run bpc and a decryptor ending up with a 10run print, is that correct?
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Aluka 7th
Amarr
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Posted - 2008.09.10 11:36:00 -
[7]
Originally by: Matthew
So yes, in this case you should only bother with a max-run ship BPC if you are using a decryptor that adds to the number of runs.
However, if the max T2 runs is higher than 1 (as it is with modules), then using a max-run BPC does make a significant difference.
This means that you should use max run BPC in ALL cases except when inventing ships AND not using decryptor.
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Rin Taleda
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Posted - 2008.09.11 02:05:00 -
[8]
Originally by: Oli Robbo
ok so say you're doing ship invention going by the above formula's.. it appears that it would be more efficient/economical to use a 1run bpc and a decryptor to get a 9run copy rather than using a 10run bpc and a decryptor ending up with a 10run print, is that correct?
You have to "run the numbers" since the invention costs vary widely as do potential profits per run, so the decryptor's effect on profit will be different for each item.
For most modules a decryptor doesn't make sense and you would typically use a max run bpc as input. Most modules have 300 as the max run bpc, although some are different.
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Lord Fitz
Project Amargosa
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Posted - 2008.09.11 12:28:00 -
[9]
Originally by: Oli Robbo
ok so say you're doing ship invention going by the above formula's.. it appears that it would be more efficient/economical to use a 1run bpc and a decryptor to get a 9run copy rather than using a 10run bpc and a decryptor ending up with a 10run print, is that correct?
It's going to depend on the cost of the max run ship BPC vs the cost of a single run, multiplied by the number you have to use to get a success, vs the value of the extra output run.
Once upon a time with expensive datacores it was always worth using a max run, these days it may be less worth it, but there is no 'rule'.
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