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Hobgoblin ll
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Posted - 2009.05.08 03:03:00 -
[1]
Proof: Let n = 0.999...
Then 10n = 9.99... 10n - n = 9.999... - 0.999... 9n = 9.000... 9n = 9 n = 9/9 = 1
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Atomos Darksun
Damage Incorporated.
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Posted - 2009.05.08 03:07:00 -
[2]
Not really, no.
Originally by: Amoxin My vent is talking to me in a devil voice...
CONVERT TO LINKIFICATION! http://myeve.eve-online.com/ingameb |

Intense Thinker
Minmatar
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Posted - 2009.05.08 03:19:00 -
[3]
I want to say you're not doing it right, but I suck at math so I can't 
Pomp FTW!!! |

Atomos Darksun
Damage Incorporated.
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Posted - 2009.05.08 03:41:00 -
[4]
Originally by: Intense Thinker I want to say you're not doing it right, but I suck at math so I can't 
Great name.
Originally by: Amoxin My vent is talking to me in a devil voice...
CONVERT TO LINKIFICATION! http://myeve.eve-online.com/ingameb |

Lance Fighter
Amarr
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Posted - 2009.05.08 03:57:00 -
[5]
actually hes doing it right.
Originally by: Akita T
 Seriously ?
 ...wow... I'm such a forum ho' !
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Dong Ninja
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Posted - 2009.05.08 04:01:00 -
[6]
It's a given that .999...=1 because in your first part of the proof you said that n=.999... You might as well have said n = 1, because any number continuing on into infinity will grow.
I'll put it another way: if n=.999... then n-.000..1 will never be reached, thus there is nothing being subtracted, so n=1.
Originally by: Xen Gin Indeed, upgrading an MS OS is like taking a **** into a cake mixture, then complaining that it doesn't taste good when it's all done.
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Taedrin
Gallente Golden Mechanization Protectorate
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Posted - 2009.05.08 04:21:00 -
[7]
Edited by: Taedrin on 08/05/2009 04:21:55 Edited by: Taedrin on 08/05/2009 04:21:35 That proof actually makes no sense to me, as you are performing arithmetic with infinity (a number which extends into infinity, to be specific). What you REALLY want to say is this:
x lim x->inf ∑ 9/(10^x) = 1 1
Here the concept of infinity is restricted to end behavior analysis, and you don't have to do any arithmetic with it.
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goodby4u
Valor Inc. Psychotic Tendencies.
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Posted - 2009.05.08 04:24:00 -
[8]
I dont like these threads, they make me feel stupid. 
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Lance Fighter
Amarr
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Posted - 2009.05.08 04:29:00 -
[9]
Originally by: Taedrin Edited by: Taedrin on 08/05/2009 04:21:55 Edited by: Taedrin on 08/05/2009 04:21:35 That proof actually makes no sense to me, as you are performing arithmetic with infinity (a number which extends into infinity, to be specific). What you REALLY want to say is this:
x lim x->inf ∑ 9/(10^x) = 1 1
Here the concept of infinity is restricted to end behavior analysis, and you don't have to do any arithmetic with it.
the proof makes perfect sense, as long as you assume that 0.99... is a number, that when subtracted from itself, gives you 0.. which.. um.. it does.
Originally by: Akita T
 Seriously ?
 ...wow... I'm such a forum ho' !
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Hobgoblin ll
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Posted - 2009.05.08 05:17:00 -
[10]
Originally by: Lance Fighter
Originally by: Taedrin Edited by: Taedrin on 08/05/2009 04:21:55 Edited by: Taedrin on 08/05/2009 04:21:35 That proof actually makes no sense to me, as you are performing arithmetic with infinity (a number which extends into infinity, to be specific). What you REALLY want to say is this:
x lim x->inf ∑ 9/(10^x) = 1 1
Here the concept of infinity is restricted to end behavior analysis, and you don't have to do any arithmetic with it.
the proof makes perfect sense, as long as you assume that 0.99... is a number, that when subtracted from itself, gives you 0.. which.. um.. it does.
This. Can be easy proven with fractions aswell: 0.111... = 1/9 9x 0.111... = 9 x (1/9) = 9/9 = 1 therefore 0.999... = 1
Why using complicated stuff like ∑ when you can prove it with simple numbers.
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Dong Ninja
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Posted - 2009.05.08 06:17:00 -
[11]
Using ∑ makes you look smart. See you gotta give concepts fancy names and formulas to go with them, or else the mathematician stop being the mathematician because everyone else knows how to do it, and we can't have that or people will start thinking they're smart.
Originally by: Xen Gin Indeed, upgrading an MS OS is like taking a **** into a cake mixture, then complaining that it doesn't taste good when it's all done.
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Giggles McHappypants
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Posted - 2009.05.08 06:32:00 -
[12]
Originally by: Hobgoblin ll Proof: Let n = 0.999...
Then 10n = 9.99... 10n - n = 9.999... - 0.999... 9n = 9.000... 9n = 9 n = 9/9 = 1
Holy crap u suck at math....10n - n = 9.999 is wrong...you dont subtract the "n" away, you would have to divide it away
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Kulmid
Asshats and Alcoholics Turbo.
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Posted - 2009.05.08 06:41:00 -
[13]
Originally by: Hobgoblin ll
Originally by: Lance Fighter
Originally by: Taedrin Edited by: Taedrin on 08/05/2009 04:21:55 Edited by: Taedrin on 08/05/2009 04:21:35 That proof actually makes no sense to me, as you are performing arithmetic with infinity (a number which extends into infinity, to be specific). What you REALLY want to say is this:
x lim x->inf ∑ 9/(10^x) = 1 1
Here the concept of infinity is restricted to end behavior analysis, and you don't have to do any arithmetic with it.
the proof makes perfect sense, as long as you assume that 0.99... is a number, that when subtracted from itself, gives you 0.. which.. um.. it does.
This. Can be easy proven with fractions aswell: 0.111... = 1/9 9x 0.111... = 9 x (1/9) = 9/9 = 1 therefore 0.999... = 1
Why using complicated stuff like ∑ when you can prove it with simple numbers.
This is a bit more shady than the OPs example because you are using fractions which are exact and using a repeating decimal that is not.
_________________
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Nomakai Delateriel
Amarr Ammatar Free Corps
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Posted - 2009.05.08 06:46:00 -
[14]
Also completely ignoring the fact that 9n in this example ISN'T 9. It's 8.999...
Or you're rounding off numbers. ______________________________________________ -My respect can not be won, only lost. It's given freely and only grudgingly withdrawn. |

Kulmid
Asshats and Alcoholics Turbo.
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Posted - 2009.05.08 07:32:00 -
[15]
Originally by: Nomakai Delateriel Also completely ignoring the fact that 9n in this example ISN'T 9. It's 8.999...
Or you're rounding off numbers.
Exactly...
(10)(.999...) = 9.9999... (9)(.999...) = 8.9999... but yet (10)(.999...)-(.999...) = 9.000...
_________________
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Nomakai Delateriel
Amarr Ammatar Free Corps
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Posted - 2009.05.08 07:45:00 -
[16]
Originally by: Kulmid
Originally by: Nomakai Delateriel Also completely ignoring the fact that 9n in this example ISN'T 9. It's 8.999...
Or you're rounding off numbers.
Exactly...
(10)(.999...) = 9.9999... (9)(.999...) = 8.9999... but yet (10)(.999...)-(.999...) = 9.000...
No. Because it's still 8.999... Otherwise you're rounding off. ______________________________________________ -My respect can not be won, only lost. It's given freely and only grudgingly withdrawn. |

HankMurphy
Minmatar Pelennor Enterprises
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Posted - 2009.05.08 07:49:00 -
[17]
OP, it is neither a fact nor is it very interesting
\o/ math fail threads ---------- Hey, sewer rat may taste like pumpkin pie, but I'd never know 'cause I wouldn't eat the filthy motherf***er. |

Shadow Devourer
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Posted - 2009.05.08 07:59:00 -
[18]
The answer involves a plane and a treadmill.
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Fi Vantage
Minmatar New Ligion
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Posted - 2009.05.08 08:07:00 -
[19]
Edited by: Fi Vantage on 08/05/2009 08:08:30
Contributing to the fail!
OP's proof is good enough. Wikipedia says so!
I prefer using the infinite series version myself.
Edit: Originally by: Shadow Devourer The answer involves a plane and a treadmill.

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KingsGambit
Caldari Knights
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Posted - 2009.05.08 08:19:00 -
[20]
Originally by: Hobgoblin ll Let n = 0.999...
Then 9n = 9.000...
Ummmm...no. -------------
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Akita T
Caldari Navy Volunteer Task Force
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Posted - 2009.05.08 08:48:00 -
[21]
The first thing you need to realize is that 0.99999999[...]9999999 is not an ACTUAL number. After that, it gets really, really easy.
Want different proof ? Here's one. 1/9 = 0.111111[...]1111111 (1/9)*9 = 1 hence, 0.999999[...]9999 = 1
Tada !
EVE issues|Mining revamp|Build stuff|Make ISK |

ReaperOfSly
Gallente Zetsubou Corp
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Posted - 2009.05.08 09:16:00 -
[22]
Yay. Unlike the other "Interesting fact" thread, the OP has done it right.  ____________________
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Nomakai Delateriel
Amarr Ammatar Free Corps
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Posted - 2009.05.08 10:37:00 -
[23]
Depends on if you retain cardinal rankings of numbers approaching infinity (in some manner).
Because if n= 0.99999 and 10n-0.999999 = 9 then if we replace the last 0.999999 in "10n-.99999 = 9" with f, then f is [1-[9x[1-n]]]. Still 0.99999, but with cardinal rankings it's still a number where f=<n. ______________________________________________ -My respect can not be won, only lost. It's given freely and only grudgingly withdrawn. |

Malvaceae Veri
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Posted - 2009.05.08 11:46:00 -
[24]
ITT: non-math guys learning the basics of infinite series.
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Yakia TovilToba
Halliburton Inc.
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Posted - 2009.05.08 12:10:00 -
[25]
Edited by: Yakia TovilToba on 08/05/2009 12:13:26
Originally by: Nomakai Delateriel
Originally by: Kulmid
Originally by: Nomakai Delateriel Also completely ignoring the fact that 9n in this example ISN'T 9. It's 8.999...
Or you're rounding off numbers.
Exactly...
(10)(.999...) = 9.9999... (9)(.999...) = 8.9999... but yet (10)(.999...)-(.999...) = 9.000...
No. Because it's still 8.999... Otherwise you're rounding off.
Dude, i found your last maths test:
Linkage
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jason hill
Caldari Clan Shadow Wolf Sylph Alliance
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Posted - 2009.05.08 13:03:00 -
[26]
errr 
destroy everything you touch |

TimMc
Gallente Brutal Deliverance Blackguard Coalition
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Posted - 2009.05.08 13:07:00 -
[27]
Rounding ftl. I've had maths teachers try similar mind****s.
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ReaperOfSly
Gallente Zetsubou Corp
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Posted - 2009.05.08 14:24:00 -
[28]
Originally by: Nomakai Delateriel
Originally by: Kulmid
Originally by: Nomakai Delateriel Also completely ignoring the fact that 9n in this example ISN'T 9. It's 8.999...
Or you're rounding off numbers.
Exactly...
(10)(.999...) = 9.9999... (9)(.999...) = 8.9999... but yet (10)(.999...)-(.999...) = 9.000...
No. Because it's still 8.999... Otherwise you're rounding off.
Clearly wrong. 9n = 10n - n = 9.99999999... - 0.999999999999... = 9. You're making the classic mistake of thinking there's an infinityeth decimal place. ____________________
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Jim McGregor
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Posted - 2009.05.08 15:25:00 -
[29]
You get born on this planet and you spend your time doing this...  ---
Originally by: Roguehalo Can you nano Titans?
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Micheal Dietrich
Caldari
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Posted - 2009.05.08 15:38:00 -
[30]
Man you people are so technical. I just round to the nearest.
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