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Dan O'Connor
Cerberus Network Dignitas.
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Posted - 2010.04.28 12:52:00 -
[1]
So. You have a box with potatoes, it weighs 87 kilograms. This box is now divided into 2 boxes. One box weighs 11 kg's less than the other one. How much does the lighter one weigh?
You can only use your head and cannot make any drawings or notes.
Go! ________________________
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Crumplecorn
Gallente Eve Cluster Explorations
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Posted - 2010.04.28 13:03:00 -
[2]
Edited by: Crumplecorn on 28/04/2010 13:07:06 Spoiler:
38kg
I there a trick to this I missed? -
Did this sig become irrelevant while I was gone? Let me know! |
Rawr Cristina
Caldari Omerta Syndicate
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Posted - 2010.04.28 13:09:00 -
[3]
38kg
that was far harder than it should have been
- Malyutka (The Virus) - |
Dan O'Connor
Cerberus Network Dignitas.
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Posted - 2010.04.28 13:12:00 -
[4]
You're both incorrect.
Keep guessing! ________________________
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Larice
Minmatar Seven Provinces
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Posted - 2010.04.28 13:13:00 -
[5]
(87 - 11)/2 = 38
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Dan O'Connor
Cerberus Network Dignitas.
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Posted - 2010.04.28 13:15:00 -
[6]
Originally by: Larice (87 - 11)/2 = 38
Incorrect formula.
Try again! ________________________
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Crumplecorn
Gallente Eve Cluster Explorations
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Posted - 2010.04.28 13:25:00 -
[7]
Edited by: Crumplecorn on 28/04/2010 13:26:18
Originally by: Dan O'Connor Result is correct...
You've had me sitting here for the last 10 minutes trying to figure out where I went wrong!
The quoted formula is based on X+Y=87 & X=Y+11 :Y+11+Y=87 :2Y=87-11 :Y=(87-11)/2 -
Did this sig become irrelevant while I was gone? Let me know! |
VanNostrum
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Posted - 2010.04.28 13:27:00 -
[8]
This is elementary school maths
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Dan O'Connor
Cerberus Network Dignitas.
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Posted - 2010.04.28 13:37:00 -
[9]
Originally by: VanNostrum This is elementary school maths
Well my brain was kinda busy for a while.
Disclaimer: I was never good at maths. Maybe you were. ________________________
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Crumplecorn
Gallente Eve Cluster Explorations
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Posted - 2010.04.28 13:39:00 -
[10]
Originally by: VanNostrum This is elementary school maths
This is why I kept looking for a trick for so long. -
Did this sig become irrelevant while I was gone? Let me know! |
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Cat o'Ninetails
Caldari Rancer Defence League
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Posted - 2010.04.28 14:27:00 -
[11]
yes this is all very well but what if i eat some of the potatoes (i do have irish roots lol)
x
My Facebook! | Safety Dance |
Slade Trillgon
Endless Possibilities Inc. Ushra'Khan
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Posted - 2010.04.28 14:43:00 -
[12]
To be honest; since the weight of the two boxes and the potatoes (seperate from the boxes) are unknown, this is impossible to answer.
Slade
:Signature Temporarily Disabled: |
Taua Roqa
Minmatar Sebiestor tribe
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Posted - 2010.04.28 15:05:00 -
[13]
worked it out in about 6 seconds and i got a C for GCSE maths.
methinks some of you doth complicate matters :P
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AdmiralJohn
The Unknown Bar and Pub Elysium Alliance
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Posted - 2010.04.28 15:30:00 -
[14]
I was asked this in high school by a teacher who though he was very very tricksy.
Giving him the answer in three seconds wiped the smirk off his face.
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Dan O'Connor
Cerberus Network Dignitas.
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Posted - 2010.04.28 16:33:00 -
[15]
Well I fail this time but I have failed harder in my life ________________________
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Culmen
Caldari Macabre Votum Morsus Mihi
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Posted - 2010.04.28 17:30:00 -
[16]
Edited by: Culmen on 28/04/2010 17:31:19
Originally by: Dan O'Connor Edited by: Dan O''Connor on 28/04/2010 13:20:16
Originally by: Larice (87 - 11)/2 = 38
// EDIT
Result is correct...
However I've been told the correct formula is
87 / 2 = 43.5
Now the 11 would also have to be divided by 2
11 / 2 = 5.5
So...
43.5 - 5.5 = 38
Basic Algebra shows the two formulas are equivalent. Its called the Distributive Property
I took about 5 seconds, but that was before I had my morning coffee and cigarette. Basically I was thinking at a primary school level at that point. and further more why do i even need a sig? |
Last Wolf
Rage For Order
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Posted - 2010.04.28 19:43:00 -
[17]
Here is a another one.
How can you mathematically make
Four 9's = 100, using each 9 only once. Oh no you don't! Incoming witty reply, ETA: 300 seconds! |
Blane Xero
Amarr The Firestorm Cartel
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Posted - 2010.04.28 20:10:00 -
[18]
Originally by: Last Wolf Here is a another one.
How can you mathematically make
Four 9's = 100, using each 9 only once.
9/9 = 1 + 99 _____________________________________ Haruhiist since December 2008
Originally by: CCP Fallout :facepalm:
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Last Wolf
Rage For Order
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Posted - 2010.04.28 20:28:00 -
[19]
Originally by: Blane Xero
Originally by: Last Wolf Here is a another one.
How can you mathematically make
Four 9's = 100, using each 9 only once.
9/9 = 1 + 99
party pooper. Took me forever to figure it out when my grandpa asked me. I never thought of using 99. Oh no you don't! Incoming witty reply, ETA: 300 seconds! |
M'ktakh
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Posted - 2010.04.28 21:19:00 -
[20]
Originally by: Dan O'Connor So. You have a box with potatoes, it weighs 87 kilograms. This box is now divided into 2 boxes. One box weighs 11 kg's less than the other one. How much does the lighter one weigh?
You can only use your head and cannot make any drawings or notes.
Go!
Thats mass, not weight.
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Pr1ncess Alia
Caldari Perkone
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Posted - 2010.04.28 21:24:00 -
[21]
way to easy
a baker had a stone he used to weigh his grain
his friend asked to borrow the stone so he loaned it to him. the next day the friend returned it to him but it was broken into 4 pieces.
the friend was incredibly sorry but the farmer had a look and told him he actually had done him a favor!
he advised that he could now measure his grain in one pound increments from one pound all the way to 40 pounds using these stones.
What do the four stones weigh?
no google you ****ers! (hint: the stones may be placed on either side of the scale when weighing the grain)
"A game that is significantly nonlinear is sometimes described as being open-ended or a sandbox, and is characterized by there being no "right way" of playing the game." |
Taua Roqa
Minmatar Sebiestor tribe
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Posted - 2010.04.28 21:35:00 -
[22]
now that is puzzling
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Taua Roqa
Minmatar Sebiestor tribe
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Posted - 2010.04.28 21:41:00 -
[23]
can the grain go on both sides too?
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Taua Roqa
Minmatar Sebiestor tribe
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Posted - 2010.04.28 21:50:00 -
[24]
is it 7.5 8.5 11.5 and 12.5?
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Akita T
Caldari Caldari Navy Volunteer Task Force
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Posted - 2010.04.28 21:52:00 -
[25]
Snark : hey, isn't one stone 14 pounds by definition ?
Well, the "original stone" must have weighed 40 pounds, at least that's almost a given. And there should be combinations of a+-b+-c+-d equal to all numbers between 1 and 40. Hmm. No idea on first look so start by random brute force. Let's see... semi-random first try... 19/11/6/4. 11-6-4=1 check, 6-4=2 check, 3... fail. Hmm.
I'll get back to you on that later
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Beginner's ISK making guide | Manufacturer's helper | All about reacting _
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Last Wolf
Rage For Order
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Posted - 2010.04.28 22:04:00 -
[26]
Edited by: Last Wolf on 28/04/2010 22:04:55
I'm just gonna do a random guess And say its the prime factors of 40.
2*2*2*5 = 40.
6 - 5 = 1 2 - 0 = 2 5 - 2 = 3 4 - 0 = 4 5 - 0 = 5 6 - 0 = 6 7 - 0 = 7 5 - 2 = 3, 3 + 5 = 8 4 - 0 = 4, 4 + 5 = 9 5 - 0 = 5, 5 + 5 = 10
I'm not doing this all the way up to 40. And this assumes you can put grain on both sides of the scales also.
But why can't you go any higher than 40?
Oh no you don't! Incoming witty reply, ETA: 300 seconds! |
Akita T
Caldari Caldari Navy Volunteer Task Force
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Posted - 2010.04.28 22:21:00 -
[27]
Let's try the reverse engineered way from 1 upwards, see if it works, and see which can be the smallest (start with 1, then 2, 3, etc)
Stone 1: 1 pound. Need to measure a 2, largest possible stone you could use next is a 3 pounder. Stone 2: 3 pound. 3 is covered, 4 is also covered, we need a 5. Largest stone that can fit is a 9 (9-3-1=5). Stone 3: 9 pound. 6 is covered (9-3), 7 is covered (9+1-3), 8 is covered (9-1), 9 is covered, and we also cover all up to 13. So now we need 14. Largest we can have is 27, so 27-(9+3+1)=14. Stone 4: 27 pound. Wait a second... 1+3+9+27=40 ! This can't possibly be that simple, can it ? Let's see if it actually does cover stuff in-between... 15 ? Lift the 1 stone, 27-(9+3)=15. 16 ? Put it on the other side, 27+1-(9+3)=16. 17 ? put the 1 back, lift the 3... 27-(9+1)=17. Hey, it works ! Just keep juggling the same way you juggled for the smaller intervals, and same logic should work for all others in-betweens too.
...so, apparently, it was that simple.
27,9,3 and 1 pounds.
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Beginner's ISK making guide | Manufacturer's helper | All about reacting _
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Taua Roqa
Minmatar Sebiestor tribe
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Posted - 2010.04.28 22:23:00 -
[28]
measuring in smaller (amounts)
(2 + 2 + 2) + (5) = 11 (5) + (5 + 2) = 12 (5 + 2) + (2 + 2 + 2) = 13 (5 + 2 + 2) + (5) = 14 (5) + (5) + (5) = 15
etc
you could measure grain accurately in any amount using small portions at a time, perhaps use grain a makeshift weight to do larger amounts at once :D
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Taua Roqa
Minmatar Sebiestor tribe
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Posted - 2010.04.28 22:27:00 -
[29]
Originally by: Akita T
Let's try the reverse engineered way from 1 upwards, see if it works, and see which can be the smallest (start with 1, then 2, 3, etc)
Stone 1: 1 pound. Need to measure a 2, largest possible stone you could use next is a 3 pounder. Stone 2: 3 pound. 3 is covered, 4 is also covered, we need a 5. Largest stone that can fit is a 9 (9-3-1=5). Stone 3: 9 pound. 6 is covered (9-3), 7 is covered (9+1-3), 8 is covered (9-1), 9 is covered, and we also cover all up to 13. So now we need 14. Largest we can have is 27, so 27-(9+3+1)=14. Stone 4: 27 pound. Wait a second... 1+3+9+27=40 ! This can't possibly be that simple, can it ? Let's see if it actually does cover stuff in-between... 15 ? Lift the 1 stone, 27-(9+3)=15. 16 ? Put it on the other side, 27+1-(9+3)=16. 17 ? put the 1 back, lift the 3... 27-(9+1)=17. Hey, it works ! Just keep juggling the same way you juggled for the smaller intervals, and same logic should work for all others in-betweens too.
...so, apparently, it was that simple.
27,9,3 and 1 pounds.
gahhhhhhhh smartypants! :P just times the number by 3 >_<
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Last Wolf
Rage For Order
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Posted - 2010.04.28 22:28:00 -
[30]
Originally by: Akita T
Let's try the reverse engineered way from 1 upwards, see if it works, and see which can be the smallest (start with 1, then 2, 3, etc)
Stone 1: 1 pound. Need to measure a 2, largest possible stone you could use next is a 3 pounder. Stone 2: 3 pound. 3 is covered, 4 is also covered, we need a 5. Largest stone that can fit is a 9 (9-3-1=5). Stone 3: 9 pound. 6 is covered (9-3), 7 is covered (9+1-3), 8 is covered (9-1), 9 is covered, and we also cover all up to 13. So now we need 14. Largest we can have is 27, so 27-(9+3+1)=14. Stone 4: 27 pound. Wait a second... 1+3+9+27=40 ! This can't possibly be that simple, can it ? Let's see if it actually does cover stuff in-between... 15 ? Lift the 1 stone, 27-(9+3)=15. 16 ? Put it on the other side, 27+1-(9+3)=16. 17 ? put the 1 back, lift the 3... 27-(9+1)=17. Hey, it works ! Just keep juggling the same way you juggled for the smaller intervals, and same logic should work for all others in-betweens too.
...so, apparently, it was that simple.
27,9,3 and 1 pounds.
Interestingly enough, those numbers are also
3^0 3^1 3^2 3^3
Oh no you don't! Incoming witty reply, ETA: 300 seconds! |
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