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Eeontasia
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Posted - 2007.09.16 18:35:00 -
[1]
does the yield stay the same? or does the asteroid deplete faster? ( i understand its obviously going to go faster because of the other one mining), but would it go faster by some factor, say if two ships mine at the same rate, would the roid deplete at twice the rate, or say, 2.1 times or something of that sort?
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Tailhook
Caldari
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Posted - 2007.09.16 18:38:00 -
[2]
the yield is based on your skills/ship/lasers used, they stay the same if you share roids with others
each roid have a given ammount of ore, mine it all, and it will pop, having more people mine it at the same time makes it go pop faster
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Akita T
Caldari Navy Volunteer Task Force
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Posted - 2007.09.16 18:47:00 -
[3]
Right now, yield has (almost) nothing to do with the asteroid, but everything with the miner's skill(s).
Ore "mined" is calculated at end of miner cycle (you can manually stop it prematurely), so whoever finishes a mining cycle first gets the ore left over in it when it pops.
Volume of ore (or ice) mined is rounded DOWN (a.f.a.i.k.) to nearest integer in ore/ice units.
So, for instance, while it almost doesn't matter for veldspar (0.1 m^3 per unit), it might matter a lot for high-end ores (16 m^3 per unit), especially if your yield is low per miner... and it's quite tragic for ice (1000 m^3 per unit).
But I digress.
Each asteroid has a limited amount of ore in it (fit and use an asteroid scanner to see how much), and it doesn't matter who mines it out, when it runs out of ore, it pops.
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LemonHamster
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Posted - 2007.09.16 18:47:00 -
[4]
No yield difference, roid pops quicker, just be careful not to cross the streams
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Thorke
Gallente
Aliastra
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Posted - 2007.09.16 18:54:00 -
[5]
 Originally by: Akita T
Volume of ore (or ice) mined is rounded DOWN (a.f.a.i.k.) to nearest integer in ore/ice units.
So, for instance, while it almost doesn't matter for veldspar (0.1 m^3 per unit), it might matter a lot for high-end ores (16 m^3 per unit), especially if your yield is low per miner... and it's quite tragic for ice (1000 m^3 per unit).
Actually skills for ice affect the cycle time of the ice mining rather than the amount of ice mined (it is always one chunck per cycle -- except in a Macinaw (sp?) where it is 2).
But I digress and the principle is the same, there is X amount in an asteroid and it doesn't matter how many characters go for it.
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Akita T
Caldari Navy Volunteer Task Force
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Posted - 2007.09.16 19:49:00 -
[6]
Originally by: Thorke
it is always one chunck per cycle -- except in a Macinaw (sp?) where it is 2
Precisely 
In a Mackinaw you can cut it short past half cycle time to get 1, but anything else you get nothing if you stop it manually... that's why I said "quite tragic". 
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Startling Revelation
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Posted - 2007.09.17 14:39:00 -
[7]
It will mean that, when one player pops the roid, running a partial cycle (ie one which doesn't yield the full amount of ore because the roid pops during it), the other player will suffer a dead cycle - one which yields no ore, and he will get no message about it. That's up to 3 wasted minutes on a strip miner, plus however long it is before he realises.
In co-operative mining situations it's always worth avoiding mining the same roid because it's simply inefficient.
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Helen Hunts
Gallente
Red Dragon Mining inc
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Posted - 2007.09.17 15:15:00 -
[8]
Also, unless it's a well stocked rock, having more than one mining laser on it can be a waste as well. Unless you're running a ship that can target fewer things than you have turrets for, (destroyers) keep just one laser on a 'roid instead of two or three. This way if you lose track of which rock is about to pop, you only lose out on one laser instead of 3. And for those who can't target as many rocks as they have turrets for, spread out those lasers as much as you can.
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Mine da rocks, make more ships.
Pop da rats, make more rigs.
Sell da gear, make more money.
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