| Author |
Thread Statistics | Show CCP posts - 2 post(s) |
Evanade
Rionnag Alba
Triumvirate.
   |
Posted - 2008.09.10 11:24:00 -
[1]
it's called 'airspeed' for a reason
---------------------------
sok alt - main got banzored |
Evanade
Rionnag Alba
Triumvirate.
|
Posted - 2008.09.10 13:35:00 -
[2]
It's just that depending on the way the problem is interpreted both answers are correct.
---------------------------
sok alt - main got banzored |
Evanade
Rionnag Alba
Triumvirate.
|
Posted - 2008.09.10 13:54:00 -
[3]
 Originally by: P'uck
So please, explain how the plane would not take off.
When i first read it (and that was really really long ago) i thought they simply meant 'any wing shaped object on wheels on a conveyor belt, moving at the same speed as the belt, so effectively standing still'
I was like 12 at the time.
Obviously if it's a real aircraft and normal thrust is applied, it will take of, albeit slightly slower as the wheels generate more friction due to turning faster to compensate for the belt under them.
---------------------------
sok alt - main got banzored |
Evanade
Rionnag Alba
Triumvirate.
|
Posted - 2008.09.15 10:38:00 -
[4]
Haha, this still going?
---------------------------
sok alt - main got banzored |
Evanade
Rionnag Alba
Triumvirate.
|
Posted - 2008.09.15 13:15:00 -
[5]
Put it this way:
If an airplane starts to take off it slowly gains speed and eventually has enough velocity so that it can take off. That's on a normal concrete runway.
Replacing the runway with a conveyor belt doesnt change anything about this. Despite the fact that the 'surface' on which the plane stands is moving it will still attain the same velocity eventually compared to the solid ground under the belt, albeit slightly slower due to the extra resistance caused by the wheels having to turn faster.
---------------------------
sok alt - main got banzored |
Evanade
Rionnag Alba
Triumvirate.
|
Posted - 2008.09.15 14:10:00 -
[6]
Edited by: Evanade on 15/09/2008 14:12:25
Edited by: Evanade on 15/09/2008 14:11:37
Originally by: Dimitryy
Edited by: Dimitryy on 15/09/2008 14:05:14
Originally by: Evanade
Put it this way:
If an airplane starts to take off it slowly gains speed and eventually has enough velocity so that it can take off. That's on a normal concrete runway.
Replacing the runway with a conveyor belt doesnt change anything about this. Despite the fact that the 'surface' on which the plane stands is moving it will still attain the same velocity eventually compared to the solid ground under the belt, albeit slightly slower due to the extra resistance caused by the wheels having to turn faster.
Then i still dont understand how the airplane gets lift. I understand that the plane will be moving at the speed it needs to relative to the ground, but since the air above the wing is standing still, thus giving no lift, how is it taking off? It seems you could show this exact situation by holding a plane still in the air and spinning the wheels really fast, i dont understand why it would take off.
Edit: what i mean by "air is standing still" is that it is not passing over the wing in any way, so there should be no lift.
The plane will still be moving relative to the solid ground and thus to the air, creating lift, and moving very fast relative to the conveyor belt. The effect of the belt on the speed of the plane is nil, efect on wheel speed is alot.
The situation you project is WRONG as the plane IS moving forward, just the wheels are spinning fatser than in the normal situation.
---------------------------
sok alt - main got banzored |
Evanade
Rionnag Alba
Triumvirate.
|
Posted - 2008.09.15 16:05:00 -
[7]
Originally by: Dimitryy
Edited by: Dimitryy on 15/09/2008 14:47:38
Edited by: Dimitryy on 15/09/2008 14:46:01
Haha i get it. Really seems simple now... the wheels are free moving, cause it's a plane, not a car 
Now i'm gonna go back and read the postings of others who made the same mistake as me.
You can laugh at them, too 
---------------------------
sok alt - main got banzored |
| |
|