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Touni Starkh
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Posted - 2010.08.27 15:02:00 -
[1]
Using the formula:
nCr = ( (n + r - 1 ) ! ) / ( r ! ( n - 1 ) ! )
Where:
nCr = the total number of Strategic Cruiser configurations available to a given cruiser
n = the total number of subsystems available to each cruiser (four options across five subsystems, total of 20)
r = the total number of subsystems used in a given configuration (one option from each of the five subsystems, total of five)
nCr = ((20 + 5 - 1)!) / (5!(20 - 1)!)
nCr = (24!) / (5!(19!))
nCr = (620448401733239439360000) / (14597412049059840000)
nCr = 42,504
Each of the four Tech III Strategic Cruisers can be configured in a total of 42,504 different combinations.
I wonder how many of those 42,504 combinations have been used since the cruisers were introduced.
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Lord Haur
Amarr
Reaction Theory
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Posted - 2010.08.27 15:09:00 -
[2]
Does that formula consider that each subsystem can only go in a certain slot?
To me it's quite simply 4^5 for the current variety of subsystems
4 options for Defence
4 optins for Electronics
4 options for Engineering
4 options for Offensive
4 options for Propulsion.
4*4*4*4*4 = 4^5 = 1024 variations per t3
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Tippia
Sunshine and Lollipops
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Posted - 2010.08.27 15:13:00 -
[3]
Edited by: Tippia on 27/08/2010 15:13:45
àyou're making it overly complicated.
You have 5 sets of 4 choices, with no real interdependencies. This gives you 4^5 possible combinations per ship across 4 ships, for a total of 4^6 = 4096 possible T3 configurations.
edit: I really need to stop queueing up replies and get beaten by a decade when I come around to answering the last of themà 
ùùù
ôIf you're not willing to fight for what you have in ≡v≡à
you don't deserve it, and you will lose it.ö
ù Karath Piki |
Jerreie
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Posted - 2010.08.27 15:14:00 -
[4]
 Originally by: Touni Starkh
Using the formula:
nCr = ( (n + r - 1 ) ! ) / ( r ! ( n - 1 ) ! )
Where:
nCr = the total number of Strategic Cruiser configurations available to a given cruiser
n = the total number of subsystems available to each cruiser (four options across five subsystems, total of 20)
r = the total number of subsystems used in a given configuration (one option from each of the five subsystems, total of five)
nCr = ((20 + 5 - 1)!) / (5!(20 - 1)!)
nCr = (24!) / (5!(19!))
nCr = (620448401733239439360000) / (14597412049059840000)
nCr = 42,504
Each of the four Tech III Strategic Cruisers can be configured in a total of 42,504 different combinations.
I wonder how many of those 42,504 combinations have been used since the cruisers were introduced.
Congratulations, you failed at fourth grade math.
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Touni Starkh
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Posted - 2010.08.27 15:52:00 -
[5]
Originally by: Jerreie
Congratulations, you failed at fourth grade math.
Explain, or get the **** out.
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Halborn
Celtic Technologies Inc.
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Posted - 2010.08.27 15:59:00 -
[6]
Great math,
One question .... What use is knowing how many different combinations I can turn my strategic cruiser into?
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CEO Celtic Technologies Inc. |
knentil
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Posted - 2010.08.27 16:01:00 -
[7]
Knowing that most of them are terrible...
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Halborn
Celtic Technologies Inc.
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Posted - 2010.08.27 16:44:00 -
[8]
Originally by: knentil
Knowing that most of them are terrible...
Ofcourse
40000 useless combinations with around 25 useful haha!
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CEO Celtic Technologies Inc. |
Tippia
Sunshine and Lollipops
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Posted - 2010.08.27 16:50:00 -
[9]
Originally by: Touni Starkh
Originally by: Jerreie
Congratulations, you failed at fourth grade math.
Explain, or get the **** out.
You're using combinatorics on things that cannot be combined. You don't have 20 subsystems to choose from, of which you pick 5 ù you have to choose between 4 subsystems, 5 times in a row (and choose 1 out of 4 races to begin with).
ùùù
ôIf you're not willing to fight for what you have in ≡v≡à
you don't deserve it, and you will lose it.ö
ù Karath Piki |
Abdiel Kavash
Caldari
Paladin Order
Fidelas Constans
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Posted - 2010.08.27 16:55:00 -
[10]
Edited by: Abdiel Kavash on 27/08/2010 16:55:48
Originally by: Lord Haur
Does that formula consider that each subsystem can only go in a certain slot?
To me it's quite simply 4^5 for the current variety of subsystems
4 options for Defence
4 optins for Electronics
4 options for Engineering
4 options for Offensive
4 options for Propulsion.
4*4*4*4*4 = 4^5 = 1024 variations per t3
For the record, this is the only correct answer so far.
___________
EVE is dying! Now for real! |
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Tippia
Sunshine and Lollipops
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Posted - 2010.08.27 16:57:00 -
[11]
Originally by: Abdiel Kavash
For the record, this is the only correct answer so far.
Pff! Mine was correct too.
ùùù
ôIf you're not willing to fight for what you have in ≡v≡à
you don't deserve it, and you will lose it.ö
ù Karath Piki |
Cipher Jones
Minmatar
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Posted - 2010.08.27 17:06:00 -
[12]
Originally by: Jerreie
Originally by: Touni Starkh
Using the formula:
nCr = ( (n + r - 1 ) ! ) / ( r ! ( n - 1 ) ! )
Where:
nCr = the total number of Strategic Cruiser configurations available to a given cruiser
n = the total number of subsystems available to each cruiser (four options across five subsystems, total of 20)
r = the total number of subsystems used in a given configuration (one option from each of the five subsystems, total of five)
nCr = ((20 + 5 - 1)!) / (5!(20 - 1)!)
nCr = (24!) / (5!(19!))
nCr = (620448401733239439360000) / (14597412049059840000)
nCr = 42,504
Each of the four Tech III Strategic Cruisers can be configured in a total of 42,504 different combinations.
I wonder how many of those 42,504 combinations have been used since the cruisers were introduced.
Congratulations, you failed at fourth grade math.
Congrats. youre a ****ing ******* and a moron.
When you say "fanboi" try to picture a fat man doing burlesque with 2 big ass fans that say CCP on one and HTFU on the other. Because that dude is me. |
Zilberfrid
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Posted - 2010.08.27 17:16:00 -
[13]
Well, 1024 then.
Now add modules.
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I like to fly around and shoot stuff. |
Tippia
Sunshine and Lollipops
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Posted - 2010.08.27 17:25:00 -
[14]
Originally by: Zilberfrid
Now add modules.
Why? They're not really a part of the configurationà
àunless you want to compare it to, say, the 7,680,000,000,000,000,000 different Titans EVE has. 
ùùù
ôIf you're not willing to fight for what you have in ≡v≡à
you don't deserve it, and you will lose it.ö
ù Karath Piki |
Intigo
Amarr
Genos Occidere
HYDRA RELOADED
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Posted - 2010.08.27 17:35:00 -
[15]
Originally by: Cipher Jones
Originally by: Jerreie
Originally by: Touni Starkh
Using the formula:
nCr = ( (n + r - 1 ) ! ) / ( r ! ( n - 1 ) ! )
Where:
nCr = the total number of Strategic Cruiser configurations available to a given cruiser
n = the total number of subsystems available to each cruiser (four options across five subsystems, total of 20)
r = the total number of subsystems used in a given configuration (one option from each of the five subsystems, total of five)
nCr = ((20 + 5 - 1)!) / (5!(20 - 1)!)
nCr = (24!) / (5!(19!))
nCr = (620448401733239439360000) / (14597412049059840000)
nCr = 42,504
Each of the four Tech III Strategic Cruisers can be configured in a total of 42,504 different combinations.
I wonder how many of those 42,504 combinations have been used since the cruisers were introduced.
Congratulations, you failed at fourth grade math.
Congrats. youre a ****ing ******* and a moron.
Not as much as the OP is.
___________________
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Cipher Jones
Minmatar
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Posted - 2010.08.27 18:54:00 -
[16]
Originally by: Intigo
Originally by: Cipher Jones
Originally by: Jerreie
Originally by: Touni Starkh
Using the formula:
nCr = ( (n + r - 1 ) ! ) / ( r ! ( n - 1 ) ! )
Where:
nCr = the total number of Strategic Cruiser configurations available to a given cruiser
n = the total number of subsystems available to each cruiser (four options across five subsystems, total of 20)
r = the total number of subsystems used in a given configuration (one option from each of the five subsystems, total of five)
nCr = ((20 + 5 - 1)!) / (5!(20 - 1)!)
nCr = (24!) / (5!(19!))
nCr = (620448401733239439360000) / (14597412049059840000)
nCr = 42,504
Each of the four Tech III Strategic Cruisers can be configured in a total of 42,504 different combinations.
I wonder how many of those 42,504 combinations have been used since the cruisers were introduced.
Congratulations, you failed at fourth grade math.
Congrats. youre a ****ing ******* and a moron.
Not as much as the OP is.
The OP used the wrong equation. I yelled so hard because he pointed out that the op got the math wrong, then got the grade level of the math wrong.
When you say "fanboi" try to picture a fat man doing burlesque with 2 big ass fans that say CCP on one and HTFU on the other. Because that dude is me. |
Thorian Baalnorn
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Posted - 2010.08.27 19:44:00 -
[17]
heres a bonus question...
the ship models change depending on fitted subs. So is their 1024 different ship models for each T3 Ship? Or did they cheat and make a few combos the same thinking no one will ever notice.
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raukosen
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Posted - 2010.08.27 20:03:00 -
[18]
Don't tell me you're that stupid
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King Rothgar
Amarrian Retribution
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Posted - 2010.08.27 20:06:00 -
[19]
Obviously you've never noticed the modular part. The ships have 5 subsections with 4 variations each. They are lego ships, block A has no impact on the looks of blocks B, C, D and E. That said, for each t3 there are only 3-4 combinations that make any sense to use. In the case of the legion, I'll make the argument that only one makes sense, the unprobable command ship setup. Any legion with guns, neuts or launchers is a lol-fit. That said I have a legion with both guns and neuts. I will confirm it's a lol-fit at a truly epically fail 150 dps (my pilgrim does 230 with the same neuting power).
Thus far you shall read, but no further; for this is my sig. |
Helen Hunts
Gallente
Red Dragon Mining inc
Red Dragon Industries
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Posted - 2010.08.27 20:12:00 -
[20]
Originally by: Thorian Baalnorn
heres a bonus question...
the ship models change depending on fitted subs. So is their 1024 different ship models for each T3 Ship? Or did they cheat and make a few combos the same thinking no one will ever notice.
... You haven't actually LOOKED at the T3 ships, have you?
The bare hull has a specific shape. Each subsystem has a unique shape and location on the hull. The lack of a subsystem would also be visible. (Yes, someone familiar with T3 ships could tell what subsystems are fitted just by looking at it)
_______________________________
Mine da rocks, make more ships.
Pop da rats, make more rigs.
Sell da gear, make more money.
Any Questions? |
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Halborn
Celtic Technologies Inc.
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Posted - 2010.08.27 21:56:00 -
[21]
OH MY LORD!!
This topic is giving me headaches. What is all this nonsense about different combinations. Surely the only one that matters is the one that works the best. Who cares about the rest of them..... Play Eve dont argue over pointless issues :)
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CEO Celtic Technologies Inc. |
Tippia
Sunshine and Lollipops
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Posted - 2010.08.27 22:07:00 -
[22]
Originally by: Halborn
OH MY LORD!!
This topic is giving me headaches. What is all this nonsense about different combinations. Surely the only one that matters is the one that works the best. Who cares about the rest of them..... Play Eve dont argue over pointless issues :)
My guess is that the OP was going for some kind of argument based on the pure overkill of the possible combinations CCP has allowed for, and how it might have been a waste of resources considering how many (few) of those are actually usedà
ùùù
ôIf you're not willing to fight for what you have in ≡v≡à
you don't deserve it, and you will lose it.ö
ù Karath Piki |
Thorian Baalnorn
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Posted - 2010.08.28 00:08:00 -
[23]
Edited by: Thorian Baalnorn on 28/08/2010 00:09:03
Originally by: Helen Hunts
Originally by: Thorian Baalnorn
heres a bonus question...
the ship models change depending on fitted subs. So is their 1024 different ship models for each T3 Ship? Or did they cheat and make a few combos the same thinking no one will ever notice.
... You haven't actually LOOKED at the T3 ships, have you?
The bare hull has a specific shape. Each subsystem has a unique shape and location on the hull. The lack of a subsystem would also be visible. (Yes, someone familiar with T3 ships could tell what subsystems are fitted just by looking at it)
I played with them a bit when they first came out, to see how they looked. I didnt play with them that much though. I knew the subs changed the appearance but didnt know if it was like adding guns to a turret ship or if the subsystems melded together in different ways. kind of like when you get the ship bug in the dock and get a "Hurridrake" ( hurricane and drake models overlapping)
But technically by what your saying their are also 1024 model variations since each sub system has a specific location and specific model that is added to a "main" model.
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n0thing
Executive Intervention
Controlled Chaos
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Posted - 2010.08.28 01:25:00 -
[24]
Originally by: Helen Hunts
Originally by: Thorian Baalnorn
heres a bonus question...
the ship models change depending on fitted subs. So is their 1024 different ship models for each T3 Ship? Or did they cheat and make a few combos the same thinking no one will ever notice.
... You haven't actually LOOKED at the T3 ships, have you?
The bare hull has a specific shape. Each subsystem has a unique shape and location on the hull. The lack of a subsystem would also be visible. (Yes, someone familiar with T3 ships could tell what subsystems are fitted just by looking at it)
Yup, they just make standalone subsystem model for each subsystem, and everytime you assemble T3 you just get em combined between each other. No need to create 1024 separate ship-models.
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Noun Verber
Gallente
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Posted - 2010.08.28 05:50:00 -
[25]
Now imagine if we ever get the fabled 5th subsystem
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Guillieme Lohran
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Posted - 2010.08.29 11:53:00 -
[26]
You mean you don't have it yet?
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Headerman
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Posted - 2010.08.29 12:36:00 -
[27]
Edited by: Headerman on 29/08/2010 12:37:14
Originally by: Abdiel Kavash
Edited by: Abdiel Kavash on 27/08/2010 16:55:48
Originally by: Lord Haur
Does that formula consider that each subsystem can only go in a certain slot?
To me it's quite simply 4^5 for the current variety of subsystems
4 options for Defence
4 optins for Electronics
4 options for Engineering
4 options for Offensive
4 options for Propulsion.
4*4*4*4*4 = 4^5 = 1024 variations per t3
For the record, this is the only correct answer so far.
4^5 is good.
Originally by: Touni Starkh
Using the formula:
nCr = ( (n + r - 1 ) ! ) / ( r ! ( n - 1 ) ! )
I have a better one...
Fail = ( (n + r - 1 ) ! ) / ( r ! ( n - 1 ) ! )
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