EVE Search - Stacking penalty explained

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dalman	Posted - 2005.01.30 23:00:00 - [1] Originally by: qyros Edited by: qyros on 30/01/2005 22:42:26 Originally by: Dust Puppy ... The shield hardeners do also have a stacking penalty so for using 2 of the same type you get (0.50.5)^((1/2)^0.25) = 0.312 or so you have a total resistance of 31.2%. ... Sorry professor, just a minor clarification and no dishonouring of your work. Resistance would be 1 - 0.312?. Yes, that is correct. When you look at resistance, the formula gives the % that go through. So for example, with 2 thermal shieldhardeners on, 0.312 0.8(from basic resistance) goes through, and the total resistance is 1 - 0.312 * 0.8. M.I.A. since 2004-07-30
dalman Finite Horizon	Posted - 2005.01.30 23:00:00 - [2] Originally by: qyros Edited by: qyros on 30/01/2005 22:42:26 Originally by: Dust Puppy ... The shield hardeners do also have a stacking penalty so for using 2 of the same type you get (0.50.5)^((1/2)^0.25) = 0.312 or so you have a total resistance of 31.2%. ... Sorry professor, just a minor clarification and no dishonouring of your work. Resistance would be 1 - 0.312?. Yes, that is correct. When you look at resistance, the formula gives the % that go through. So for example, with 2 thermal shieldhardeners on, 0.312 0.8(from basic resistance) goes through, and the total resistance is 1 - 0.312 * 0.8. Am I forced to have any regret? I've become the lie, beautiful and free In my righteous own mind I adore and preach the insanity you gave to me
dalman	Posted - 2005.01.31 14:42:00 - [3] Originally by: Corair Does the bonus^(n^0.75) formula apply to things like Heatsinks and Ballistic controls? I stacked several Ballistic controls and it showed the number as if there were no penalties. Could just be a case of "things aren't as they seem," but i'd like to find out. Thanks (btw, if the answer was above somewhere, my appologies) Yes. It applies exactly the same on both damage and ROF bonus. Originally by: Sentani how about the stack pen on the sensor damps ? Works the same. tech 1, -50%, gives a 0.5 multiplier. So, with 2 that is (0.5*0.5)^((1/2)^0.25) = 0.312x multiplier. (=~-69% to range). Same way with lock time. M.I.A. since 2004-07-30
dalman Finite Horizon	Posted - 2005.01.31 14:42:00 - [4] Originally by: Corair Does the bonus^(n^0.75) formula apply to things like Heatsinks and Ballistic controls? I stacked several Ballistic controls and it showed the number as if there were no penalties. Could just be a case of "things aren't as they seem," but i'd like to find out. Thanks (btw, if the answer was above somewhere, my appologies) Yes. It applies exactly the same on both damage and ROF bonus. Originally by: Sentani how about the stack pen on the sensor damps ? Works the same. tech 1, -50%, gives a 0.5 multiplier. So, with 2 that is (0.5*0.5)^((1/2)^0.25) = 0.312x multiplier. (=~-69% to range). Same way with lock time. Am I forced to have any regret? I've become the lie, beautiful and free In my righteous own mind I adore and preach the insanity you gave to me

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