Clansworth
Point-Zero
SMASH Alliance
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Posted - 2008.02.27 01:15:00 -
[1]
Edited by: Clansworth on 27/02/2008 01:17:28
I like the idea of multi-ore asteroids, and have always thought it made good sense. I even proposed a very similar idea a while ago, though it was burried in another long mining overhaul thread. (http://oldforums.eveonline.com/?a=topic&threadID=579110&page=3#83) if you care to look back.
I did the yield calcs a bit different though. While an asteroid would have different compositions, they would not yield fractional ores. This results in the more valuable ores (having larger sizes) getting lost in the rounding (truncating, actually). Crystals help this a lot though, by boosting the yield for that ore higher, getting it past the rounding problem. Some sample calcs I did are below:
Object Size Veld Scor Plag Pyro
Asteroid 1 7806m¦ 7432m¦(95.2%) 345m¦ (4.4%) 24m¦ (0.3%) 5m¦(0.06%)
Asteroid 2 1373m¦ 534m¦(38.9%) 293m¦(21.3%) 546m¦(39.8%) 0m¦ (0.0%)
Asteroid 3 2777m¦ 25m¦ (0.9%) 2752m¦(99.1%) 0m¦ (0.0%) 0m¦ (0.0%)
Ore Yield = ROUND_DOWN( [ROID_ORE_CONTENT] / [ROID_SIZE] * [LASER_YIELD] / [ORE_SIZE] )
and limited to [ROID_ORE_CONTENT]
the Tech 1 crystal's specialty multiplier 1.65, and non specialty yield is 0.20.
So, From Asteroid 1, using a Miner I (40m¦/cycle)
Veldspar = ROUND_DOWN( [ 7432m¦ ] / [ 7806m¦ ] * [ 40m¦/cycle] / [ 0.1m¦/u] ) = 380u/cycle
Scordite = ROUND_DOWN( [ 345m¦ ] / [ 7806m¦ ] * [ 40m¦/cycle] / [0.15m¦/u] ) = 11u/cycle
Plagio = ROUND_DOWN( [ 24m¦ ] / [ 7806m¦ ] * [ 40m¦/cycle] / [0.35m¦/u] ) = 0u/cycle
Pyroxeres = ROUND_DOWN( [ 5m¦ ] / [ 7806m¦ ] * [ 40m¦/cycle] / [ 0.3m¦/u] ) = 0u/cycle
Total Yield = 39.6m¦/60 seconds = 39.6m¦/min
As you can see, even though there are traces of Plagioclaise and Pyroxeres in the rock, they are to miniscule for the crude Miner I to grab a hold of. Modulated lasers on the other hand will have a better change at getting the small stuff.
So from asteroid 1, with a MDCM II and Plagioclaise I crystal fitted:
(120 * 0.2 = 24m¦/cycle unspecialized, 120 * 1.65 = 198m¦/cycle specialized)
Veldspar = ROUND_DOWN( [ 7432m¦ ] / [ 7806m¦ ] * [ 24m¦/cycle] / [ 0.1m¦/u] ) = 228u/cycle
Scordite = ROUND_DOWN( [ 345m¦ ] / [ 7806m¦ ] * [ 24m¦/cycle] / [0.15m¦/u] ) = 7u/cycle
Plagio = ROUND_DOWN( [ 24m¦ ] / [ 7806m¦ ] * [198m¦/cycle] / [0.35m¦/u] ) = 1u/cycle
Pyroxeres = ROUND_DOWN( [ 5m¦ ] / [ 7806m¦ ] * [ 24m¦/cycle] / [ 0.3m¦/u] ) = 0u/cycle
Total Yield = 24.2m¦/180 seconds = 8.1m¦/min
As you can see using the Plagioclaise crystal on a rock that has only trace amounts of plagioclaise will yield some plagio, but overall be pretty ineffective. Using that crystal on the Second roid though, which is more rich in its target ore, results in the following:
Veldspar = ROUND_DOWN( [ 534m¦ ] / [ 1373m¦ ] * [ 24m¦/cycle] / [ 0.1m¦/u] ) = 93u/cycle
Scordite = ROUND_DOWN( [ 293m¦ ] / [ 1373m¦ ] * [ 24m¦/cycle] / [0.15m¦/u] ) = 34u/cycle
Plagio = ROUND_DOWN( [ 546m¦ ] / [ 1373m¦ ] * [198m¦/cycle] / [0.35m¦/u] ) = 224u/cycle
Pyroxeres = ROUND_DOWN( [ 0m¦ ] / [ 1373m¦ ] * [ 24m¦/cycle] / [ 0.3m¦/u] ) = 0u/cycle
Total Yield = 92.8m¦/180 seconds = 30.93m¦/min
Using the tuned crystal on a rock that is mostly its target will be very effective:
Rock 1 with a Veldspar crystal:
Veldspar = ROUND_DOWN( [ 7432m¦ ] / [ 7806m¦ ] * [198m¦/cycle] / [ 0.1m¦/u] ) = 1885u/cycle
Scordite = ROUND_DOWN( [ 345m¦ ] / [ 7806m¦ ] * [ 24m¦/cycle] / [0.15m¦/u] ) = 7u/cycle
Plagio = ROUND_DOWN( [ 24m¦ ] / [ 7806m¦ ] * [ 24m¦/cycle] / [0.35m¦/u] ) = 0u/cycle
Pyroxeres = ROUND_DOWN( [ 5m¦ ] / [ 7806m¦ ] * [ 24m¦/cycle] / [ 0.3m¦/u] ) = 0u/cycle
Total Yield = 189.55m¦/180 seconds = 63.18m¦/min
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